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My fracture, and what it does to the pad

Type in the fracture you actually believe in — its half-length, its average width, its height — and the proppant that filled it. The page reads that against your pad plan's own stage spacing, rock stiffness and slurry volume: the squeeze it lays on the next stage, the fluid efficiency the volume implies, and how far the pack reaches. Nothing here changes the plan.

The fracture and its proppant
No fluid imported yet, so this reads against the library starting plan — 250 ft spacing, 6 clusters.

Fracture geometry

Proppant properties

Width is entered as an average over the face; the shadow kernel needs the peak aperture, so it uses 0.178 in — the elliptical section of the same fracture.

What this fracture does to the plan
A 900 ft by 0.140 in fracture lays 109 psi on the next stage at 250 ft spacing and implies 35.9 % fluid efficiency, with pack out to 92 ft.
Squeeze on the next stage
109 psi
1.4 % of closure stress
Fluid efficiency implied
35.9 %
3,024 ft³ stored of 8,423 ft³ pumped per cluster
Propped half-length
92 ft
limited by pack volume
NumberValueHow it was reached
Squeeze on the next stage109 psiEvery one of the 6 clusters casts its own shadow at 42 ft apart, summed at the plan's 250 ft stage spacing.
Squeeze as a share of closure stress1.4 %Against the plan's 7500 psi minimum stress.
Spacing that holds squeeze to 200 psi188 ftDistance at which this fracture's summed shadow falls to 200 psi.
Stored volume, one fracture3,024 ft³2 × (4/5) × half-length × height × average width — the PKN taper.
Net pressure this width implies195 psiw_max × E′ ÷ (2 × height), on the plan's 4.73 Mpsi plane-strain modulus.
Net pressure the rock's strength asks for at the tip5 psiK_IC = 1000 psi·√in as the plan carries it — no strength in the core — over √(π x_f).
Net pressure left over after the tip takes its share190 psiThis aperture drives the tip with 190 psi to spare on the plan's fitted strength.
How far this net pressure can drive the tip1 ftx_f = K_IC² ÷ (π p_net²) on the plan's fitted 1000 psi·√in, against the 900 ft entered.
Stress the next stage's rock carries7,609 psi7500 psi of fitted minimum stress plus this stage's 109 psi squeeze.
Pressure inside the fracture while it grows7,695 psi7500 psi of fitted minimum stress plus the 195 psi this aperture implies.
Fluid efficiency this geometry implies35.9 %Stored volume ÷ the 8423 ft³ of slurry each cluster took.
Volume left in the rock5,399 ft³Whatever the pumped slurry did not store in the fracture.
Propped half-length92 ftSet by pack volume; 10 % of the hydraulic length carries pack.
Areal proppant on the propped face1.238 lb/ft²Pack spread over the settled bank band, 95 ft tall.
My fracture against the solver's
Press “Solve the plan to compare” and the kernel's own geometry lands beside yours.
NumberMineSolverΔ
Hydraulic half-length900 ftnot solved yet
Average width0.140 innot solved yet
Height180 ftnot solved yet
Propped half-length92 ftnot solved yet
Squeeze on the next stage109 psinot solved yet
Fluid efficiency35.9 %not solved yet
If the fracture were different
The same plan, the same proppant, only the geometry moved — so you can see which of length and width the squeeze and the efficiency actually follow.
CaseHalf-lengthAverage widthSqueezeEfficiencyPropped
Half the length450 ft0.140 in109 psi18.0 %94 ft
A quarter shorter675 ft0.140 in109 psi26.9 %93 ft
As entered900 ft0.140 in109 psi35.9 %92 ft
A quarter longer1,125 ft0.140 in109 psi44.9 %92 ft
Half again as long1,350 ft0.140 in109 psi53.9 %92 ft
A third narrower900 ft0.093 in73 psi23.9 %140 ft
A third wider900 ft0.187 in145 psi47.9 %69 ft
Wider and longer1,125 ft0.187 in145 psi59.8 %69 ft
How each number was reached
Every step, in the order the page took it. The plan itself lives on the pad plan page.
  • Width entered as an average, so the kernel's peak aperture is 0.178 in (elliptical section, 4/π).
  • Plane-strain modulus 4.73 Mpsi from the plan's 4.50 Mpsi and ν = 0.220.
  • Minimum stress 7500 psi as the plan carries it.
  • Squeeze summed over 6 clusters 42 ft apart, Olson β = 1.
  • Slurry per cluster 8423 ft³ from 9000 bbl per stage.
  • Proppant per cluster 75000 lb, of which 29 % is taken to reach this fracture.
  • Tip pressure 5 psi = 1000 psi·√in ÷ √(π × 10800 in), on the plan's fitted toughness, against the 195 psi this aperture implies.
  • Stress on the neighbour 7609 psi = 7500 psi minimum stress + 109 psi squeeze; the fracture itself has to be held at 7695 psi to keep growing.